6x^2+50x-4070=0

Solution for 6x^2+50x-4070=0 equation:

6x^2+50x-4070=0

a = 6; b = 50; c = -4070;
Δ = b2-4ac
Δ = 502-4·6·(-4070)
Δ = 100180
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{100180}=\sqrt{4*25045}=\sqrt{4}*\sqrt{25045}=2\sqrt{25045}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-2\sqrt{25045}}{2*6}=\frac{-50-2\sqrt{25045}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+2\sqrt{25045}}{2*6}=\frac{-50+2\sqrt{25045}}{12}
$